First, this is a problem of so-called "quasi experimental studies". But all these quasi experiments need a time
dimension. Can we design an experimental study that does not use a control
group or multiple measurements in time?
If we assume additivity of campaigns, all we have to do is
to get as many independent equations as is the count of unknown variables. For
example, let's imagine we have two campaigns, the first one with response rate
A and the second one with the response rate B. Let's also imagine that if we do
not expose a user to a campaign, then the response rate of the user is N. And
let's imagine that we can combine campaigns, either because each is using a
different channel or because each is to a different product. Than we can set up
3 campaigns:
N+A = 5
N+B = 7
N+A+B = 9
The first group of users is exposed to the first campaign
and the response rate is 5%. The second group to users is exposed to the second
campaign and the response rate is 7%. And the last group of users is exposed to
both campaigns and the resulting response rate is 9%.
Since we have 3 independent equations and 3 unknown
variables, we can calculate that the first campaign has uplift 9-7 = 2 percent
points and that the second campaign has uplift 9-5 = 4 percent points.
Of course, this approach neglects interactions between the
campaigns. But we can model interactions as well. In this example, let's consider 3
campaigns with following response rates:
N+A = 5
N+B = 7
N+A+B+AB = 9
N+C = 8
N+A+C = 3
where AB represents an interaction of two first two
campaigns. We can put the equation into a matrix form:
matrix = [1
1 0 0 0; 1 0 1 0 0; 1 1 1 1 0; 1 0 0 0 1; 1 1 0 0 1]
response =
[5; 7; 9; 8; 3]
x = [?; ?;
?; ?; ?]
Where x is a vector of the unknown variables. It holds that:
matrix*x =
response
With linear algebra:
x =
inv(matrix) * response
We can get that x = [10; -5; -3; 7; -2].
To get higher confidence in the estimates it is possible to
use more independent equations than is the count of unknown variables and fit
the unknown variables with least squares estimate (or other method of your
choice).
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